Q In how many ways can 4 boys and three girls be arrange in a straight line, If there are 8 boys and five girls to choose from?
AM 8C4 = 70 ways of choosing the boys5C3 = 10 ways of choosing the girls
Then 7! = 5040 ways of arranging the chosen boys and girls
Giving a total of 70 x 10 x 5040 = 3528000 ways.
Me I thought that and didn’t feel confident about the answer .. would there be limit beneath the seven factorial for genericboys or girls being in similar position?
AM No, only if they're identical boys / identical girls. If unconvinced, treat the boys as B1, B2, B3, B4, and the girls as G1, G2 and G3 to see that you are arranging 7 unique elements.
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